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help write in vertex form f(x)=8x^2 + 8x - 12
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I think that should be your answer
it's asking for an equation, not a graph start by writing parentheses around the first two terms f(x)= (8x^2 + 8x) - 12
then we factor out 8 from the expression inside the parentheses f(x) = 8(x^2+x) - 12
then we take the coefficient in front of x (which is 1), divide it by 1, and then square it
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(1/2)^2 = 1/4, and then we add this number to the inside of the parentheses f(x) = 8(x^2+x+1/4) - 12 know where to go from here?
no
factor (x^2+x+1/4)
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