Question

A ball at rest starts rolling down a hill with a constant acceleration of 3.2 meters/second2. What is the final velocity of the ball after 6.0 seconds?

Answer 1

so the formula for acceleration is \[A = \frac{ V1-V0 }{ \Delta T }\]

so A is 3.2m/s^2
V0 is 0s
T is 60s
and you need to find V1

so edit the formula to find V1
\[V0 + \Delta T * A = V1\]
im not good at physics you should ask there not in language & culture