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Please help, precalc test tomorrow! Question is find all solutions on interval 0 less than or equal to theta less than or equal to 2 pi for 2sintheta+sqrt3=0 I'm confused on how to get 2theta.....
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Okay. 2sinθ+1 = 0 2sinθ = -1 sinθ = -1/2 sin π/6 = 1/2, so using that as a reference angle in QIII and QIV, we get the solutions π + π/6 and 2π - π/6
Hope this helped. Have a great day!
its not 2 sin theta, it's sin(2theta)
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