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Find the axis of symmetry of the graph of the function. f(x) = 2x2 - 4x
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\[\huge\rm Ax^2+Bx+C\] quadratic equation you can use formula -b/2a to find axis of symmetry
@AbbyWuvsChu talk to me
which is also the x-coordinate of the vertex a=leading coefficient b=coefficient of x term
-4/4=-1
the formula is \[\rm \frac{ -b }{ 2a }\] and the b value is also negative
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so it should be \[\frac{ -(-4) }{ 4 }\]
1 oh ok
yes that's correct
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