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Mathematics 13 Online
OpenStudy (anonymous):

Solve: 4 - |3x + 1| < 2

pooja195 (pooja195):

Add -4 to both sides. −|3x+1|+4+−4<2+−4 −|3x+1|<−2 Divide both sides by -1 (to get rid of that neg sign −|3x+1|/-1<−2/-1 |3x+1|>2 An absolute value can have a neg and pos solution

pooja195 (pooja195):

3x+1>2(Possibility 1) <---isolate x 3x+1<−2(Possibility 2) <-----isolate x

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