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Use the law of cosines to determine the length x in each figure when a = 4 cm and b = 18 cm. Leave your answers in terms of radicals. a) x= ? b) x= ?
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A)
B)
I keep getting 340-72 √3, but how can I simplify it?
probably can't
not sure it is right though
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\[x^2=4^2+18^2-2\times 4\times 18\times \frac{\sqrt3}{2}\]
but that is \(x^2\) \(x\) is the square root of that number
So I did it incorrectly?
I tried answer your question, but..... Please follow here:
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