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what is the common ratio for the geometric sequence 1/128, 1/16, 1/2, 4
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divide the 1st term by 2nd term
\[\frac{ 1 }{ 128 }\div \frac{ 1 }{ 16 }=\frac{ 16 }{ 128 }=1/8\]
so it would be 1/8?
yeah
i thought it would had been -4
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no.. for germetric series common ratio is given by \[\frac{ a_2 }{ a_1 }=\frac{ a_3 }{ a_2 }=.....\]
ooohhhh ok thanks alot :D
now you check that the result is true by dividing the third term by 2nd term
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