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what is the 7th term of the geometric sequence 3/128, 3/16 ,3/2 ,12
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you can say\[\frac{3}{2^{(7-3n)}}\] for nth term of the sequence
for example, put n=0 if you want first term
put n=1, if you want 2nd term
put n = 2 if you want 3rd term
and put n = 6 for the 7th term
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get it?
yes
\[7th \ term = \frac{3}{2^{7 - 6*3}}\]
\[\frac{3}{2^{-11}}\]\[3*2^{11}\]
3*2048 = 6144
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i got 6144
nice:) bye
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