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Factor: 6x + 9xy + 10y + 15y2 (5x + 3y)(2y + 3) (3x + 5y)(3y + 2) (5x - 3y)(2y - 3) (3x - 5y)(2 - 3y)
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start by grouping the terms into two groups (6x + 9xy) + (10y + 15y2) then factor each group, know where to go from here?
no i dont
factor the first group (6x + 9xy) what is the greatest common factor of 6x and 9xy?
3x
good, so (6x + 9xy) = 3x(2+3y) now factor (10y + 15y2) using the same process
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5y
good, so (10y + 15y2) = 5y(2+3y) so far we have 5y(2+3y) + 3x(2+3y) which equals (5y+3)(2+3y)
small typo
(5y+3x)(2+3y)
thanks pal
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