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When the function f(x) = 4(2)x is changed to f(x) = 4(2)x − 13, what is the effect? There is no change to the graph because the exponential portion of the function remains the same. The x-intercept is 13 spaces higher. The y-intercept is 13 spaces lower. All input values are moved 13 spaces to the left.
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idk if its C or D
i think its C
Let's set x=0 and explore what happens. The initial function will have a y intercept of 0. The second function will have a y intercept of -13. Setting y=0 yields similar results. The first function has an x intercept of 0, while the second function will have an x intercept of 13.
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