Question

Solve for x.

−ax + 2b > 8
x < the quantity negative 2 times b plus 8 all over negative a
x > the quantity negative 2 times b plus 8 all over negative a
x < the quantity 2 times b minus 8 all over negative a
x > the quantity negative 2 times b minus 8 all over a

Answer 1

\[-ax + 2b > 8\]
subtract 2b from both sides
\[-ax > 8 - 2b\]
divide both sides by -a and flip the sign of the inequality
\[x < \frac{ 8-2b }{ -a }\]

Answer 2

Thank you!

Answer 3

yw