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If (7^2)^x = 1, what is the value of x? Explain your answer.
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anything raised to the 0 power is 1
i dont understand
that's just a property of exponents. 3^0 = 1 49^0 = 1 (ax² - 5)^0 = 1 If you get 1 as the result, (and the base isn't 1), then the exponent has to be 1
so youre saying 0 = 1 ?
no. I'm saying that x = 0.
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ohhhhhhhhhhhhhhhhh ok
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