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Mathematics 9 Online
OpenStudy (korosh23):

Pre-cal 12 Question! Determine the equation in factored form for the polynomial graph. I need the value of 'a' as well. Ex. f(x)= ax^3 +x^2 + x +4 Please wait for the attachment.

OpenStudy (korosh23):

ganeshie8 (ganeshie8):

Look at the given graph, what are the x intercepts ?

OpenStudy (korosh23):

Well, I know that x-int are --> x=-2 multiplicity of 1 x=1 multiplicity of 2 x=3 multiplicity of 1

ganeshie8 (ganeshie8):

Excellent! next use factor theorem to write an expression for the polynomial

ganeshie8 (ganeshie8):

if \(x=a\) is a zero, then \((x-a)\) is a factor of the polynomial

OpenStudy (korosh23):

Yes, until now, this is what I think it is p(x)= (x+2)(x-1)(x-3) we need y-int and value of a

OpenStudy (korosh23):

sorry (x-1)^2

ganeshie8 (ganeshie8):

use the information about multiplicity too

ganeshie8 (ganeshie8):

looks good !

ganeshie8 (ganeshie8):

p(x)= a(x+2)(x-1)^2(x-3)

ganeshie8 (ganeshie8):

lets see if we can find the value of \(a\)

OpenStudy (korosh23):

ok

ganeshie8 (ganeshie8):

all we're given is a graph so stare at the graph and see if we could use something. .

OpenStudy (korosh23):

y-int?

ganeshie8 (ganeshie8):

yeah give it a try

OpenStudy (korosh23):

ok wait a moment

ganeshie8 (ganeshie8):

it seems y intercept is -3 ?

OpenStudy (korosh23):

yeah I think so so, (0,-3)

ganeshie8 (ganeshie8):

plug that in and find \(a\)

OpenStudy (korosh23):

so, this is what I think it is p(x)=a(x-3)(x-1)^2(x+2) -3= a(-3)(-1)^2(+2) -3=-6a so a= -3/-6= 0.5

ganeshie8 (ganeshie8):

looks good !

OpenStudy (korosh23):

haha thank you very much for walking me through it. :)

ganeshie8 (ganeshie8):

np:)

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