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here you have to replace \(m=9\), so we get: \[a = 28500 - 1800 \cdot 9 = ...?\]
16,700 *9 right?
hint: here is next step: \[a = 28500 - 1800 \cdot 9 =28500-16200= ...?\]
we have to compute \(1800 \cdot 9\) first
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its 16200 or 16700 @Michele_Laino
is that minus 9 or times?
we have \(1800 \cdot 9= 16200\)
\(m\) represents time mesured in minutes
so 16200-28500
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so, we have to compute this: \[\huge \begin{gathered} a = 28500 - \left( {1800 \cdot 9} \right) = \hfill \\ \hfill \\ = 28500 - 16200 = ...? \hfill \\ \end{gathered} \]
12300
correct!
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