Question

Solved!

Answer 1

this one will factor to
(2x - 5)(2x - 1)

Answer 2

so we have 2x - 5 = 0 or 2x - 1 = 0
2x = 5 or 2x = 1
solution set is {5/2 , 1/2)

Answer 3

Thanks i've been struggling on questions like these for a minute any idea part c?

Answer 4

Also if you have any tips that'll help too cause i look at my books and lessons and like i can never really understand it

Answer 5

with this one there are no real factors so you can use the quadratic formula

x = [-b +/- sqrt(b^2 - 4ac)] / 2a

where a,b and c are the coefficients in the equation ax^2 + bx + c = 0

Answer 6

here a = 2 , b = -10 and c = 3

Answer 7

thanks again and so we get 5 +/- sqroot 19 /2?

Answer 8

yea

Answer 9

so that is the answer or do i have to get x?

Answer 10

oh hold on

x = [-(-10) +/- sqrt (100 - 4*2*3)] / 4

Answer 11

lol - I'm getting confused here!!!

x = 10 + 2 sqrt19
------------
4

= { 5/2 + sqrt19 / 2 , 5/2 - sqrt19/2}

Answer 12

oh second line should be +/-

Answer 13

Okay so its like i said right ? haha! so then is that my answer or is there one more step?

Answer 14

no that is the answer there are 2 roots.

Answer 15

Okay thank you so much! you made it so much easier!

Answer 16

yw