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4i(-3-yi)+7=27-12i What is the value of y?
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first you need to expand the LHS
4i(-3-yi) = -12i - 4yi^2 = ?
What's LHS?
I'm not sure how you did that or how it helps me find the y value but I copied that question verbatim so I can't expand on anything
LHS is the left hand side of the equation which I've just expanded and now I'm asking you to do the next step?
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Is it 4i(3-yi)=-12i+4
I mean+ 4y
yes it's -12i + 4y so we now have -12i + 4y = 27 - 12i Now solve for y. Add 12i to both sides and what do we get?
You get 4y=27?
Then you get y= 6.75?
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