Question

Solve the system by the substitution method. Show your work.

2y - x = 5
x2 + y2 - 25 = 0

Answer 1

solve for x in the first equation first.

2y - x = 5
add x to both sides and subtract 5 from both sides
2y - 5 = x

x= 2y - 5

now substitute this value into the second equation and solve for y.

Answer 2

(2y - 5)^2 + y^2 - 25 = 0
4y^2 - 20y + 25 + y^2 - 25 = 0
5y^2 - 20y = 0
5y(y - 4)=0

now solve this for y.

Answer 3

u will get y=0 and y=4

now sustitute these y-values into the equation x=2y - 5 and solve for x. u should get two pairs of solutions

Answer 4

thanks i got it already!

Answer 5

np :)