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Algebra
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find the value that completes the square and then rewrite as a perfect square answers 1) x^2 - 12x + __
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step 1) take half of the x coefficient (in this case, the x coefficient is -12) step 2) square the result from step 1. This is the missing value that goes in the blank
so like this? \[\sqrt{-6}\]
square, not square root
(-6)^2 = ???
Ohhhhhh my bad lol aight thanks!
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