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What is the Value of h when the function is converted to vertex form? F(x)=x2+10x+35
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do you know what vertex form is??
um i'm not sure
this is the form \[=a(x-h)^2 +k\]
(h,k) is the vertex
the easiest way is : ax^2 + bx + c F(x)=x2+10x+35 h= -b/2a plug in b=10 a=1 so -10/2(1) what is h
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hold on
h=-5
yes that is your h value.
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