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Write a quadratic equation with roots of 4 + 3i and 4 – 3i. Show all your work.
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this will be (x + (4 + 3i))( x + (4 - 3i)) = 0 expand this and you'l get your equation
oops i made a mistake sorry it should be negatives after the x 's
(x - (4 + 3i))( x - (4 - 3i)) = 0
I'll start you off;- = x^2 - x(4 - 3i) -x(4 + 3i) +(4 + 3i)(4 - 3i) = 0
recall that i^1 = -1
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x^2 - 4x + 3i - 4x - 3i + (16 - 12i + 12i- 3 i^2)
now you can simplify this Note that the 3i' s and 12i's cancel out.
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