Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
OpenStudy (anonymous):
Okay. I can help. Give me a moment @Tayssir
OpenStudy (anonymous):
ok thank you @Tom_Boy_Rebel
HanAkoSolo (jamierox4ev3r):
really quickly @Tayssir have you learned the law of cosines and law of sines yet?
OpenStudy (anonymous):
no
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
Directrix (directrix):
@Tayssir Which problem are you wanting to do?
Recall right triangle trig?
OpenStudy (anonymous):
i attatched the page i need help with i havent learned it yet @Directrix
Directrix (directrix):
I will help with one problem and then you'll know how to do the page of problems.
Give me a problem number to do, okay?
OpenStudy (anonymous):
#1 @Directrix
Directrix (directrix):
#1 is not on the sheet. #14 is the first problem I see. Click on the uploaded sheet and see what you can see.
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
ya i ment the first question @Directrix
OpenStudy (xapproachesinfinity):
ok so first question #14
let's do it and then you do the rest
OpenStudy (xapproachesinfinity):
we have a right triangle
to find a and b we can use sin, cos
we are given the angle measure of 37 and hypotenuse 10
recall that sin is opposite over hypotenuse
so \[\sin (37)=\frac{b}{10}\Longrightarrow b=10\sin (37)\]
now for a we use cos
cos if you remember is adjacent over hypotenuse
\[\cos(37)=\frac{a}{10} \Longrightarrow a=10\cos(37)\]
OpenStudy (xapproachesinfinity):
for final answer you need a calculator
OpenStudy (xapproachesinfinity):
all of others problems need to be done in a similar way
Still Need Help?
Join the QuestionCove community and study together with friends!