geometry help
Okay. I can help. Give me a moment @Tayssir
ok thank you @Tom_Boy_Rebel
really quickly @Tayssir have you learned the law of cosines and law of sines yet?
no
@Tayssir Which problem are you wanting to do? Recall right triangle trig?
i attatched the page i need help with i havent learned it yet @Directrix
I will help with one problem and then you'll know how to do the page of problems. Give me a problem number to do, okay?
#1 @Directrix
#1 is not on the sheet. #14 is the first problem I see. Click on the uploaded sheet and see what you can see.
ya i ment the first question @Directrix
ok so first question #14 let's do it and then you do the rest
we have a right triangle to find a and b we can use sin, cos we are given the angle measure of 37 and hypotenuse 10 recall that sin is opposite over hypotenuse so \[\sin (37)=\frac{b}{10}\Longrightarrow b=10\sin (37)\] now for a we use cos cos if you remember is adjacent over hypotenuse \[\cos(37)=\frac{a}{10} \Longrightarrow a=10\cos(37)\]
for final answer you need a calculator
all of others problems need to be done in a similar way
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