Question

Two separate bacteria populations grow each month and are represented by the functions f(x) = 3x and g(x) = 7x + 6. In what month is the f(x) population greater than the g(x) population?

Answer 1

@sleepyjess

Answer 2

@pooja195

Answer 3

well let's first figure out what month they might be equal

that would be f(x) = g(x)
or 3x = 7x + 6
can you solve for x from there?

Answer 4

i don't think so

Answer 5

3x = 7x + 6

Answer 6

i think it would be after 2 months

Answer 7

oh wait...
\[f(x) = 3x ~or~ f(x) = 3^x\]

Answer 8

the first one

Answer 9

then I don't think this question is right :-/

Answer 10

it definitely is

Answer 11

Two separate bacteria populations grow each month and are represented by the functions f(x) = 3x and g(x) = 7x + 6. In what month is the f(x) population greater than the g(x) population?

Month 1
Month 2
Month 3
Month 4

Answer 12

I still don't think it's possible... sorry

Answer 13

well if you had to guess what would it be

Answer 14

@inkyvoyd @imqwerty @ganeshie8 help

Answer 15

\[f(x)=3x\]\[g(x)=7x+6\]\[g(x)=3x+4x+6\]
we know that 3x=f(x)\[g(x)=f(x)+4x+6\]

we can clearly see that g(x) will be greater than f(x)

what ever the value of f(x) be g(x) will have 4x+6 more add to it

so g(x)>f(x)

Answer 16

oh wait i didn't read the ques well

Answer 17

so none of the answers are wrong?

Answer 18

but nvm the ques is wrong if x is the number of week

Answer 19

number of months

Answer 20

yeah g(x) will be greater than f(x) no matter what

Answer 21

well then what should i put just 2 months or something

Answer 22

Never.
Even without the +6, 7x will always be greater than 3x, except if x is negative, which populations cannot be.

Answer 23

u can also try the options to find out the populations
liek
no where f(x) is greater than g(x)

Answer 24

im sorry the 3x is supposed to be 3^x..... like an exponent

Answer 25

oooooh

Answer 26

lol sorry

Answer 27

just try the options out
this is the easiest way
not much thinking not much time waste (B

Answer 28

i think its 2 months

Answer 29

I asked you that ;-;

Answer 30

thats wrong

Answer 31

sorry @jigglypuff314

Answer 32

what did u do?

Answer 33

idk lol i have no idea

Answer 34

maybe 4

Answer 35

(:

Answer 36

don't guess u shuld be sure about it

Answer 37

was that right?

Answer 38

lol
try plugging in 1 for x
into 3^x
then into 7x + 6
and compare them

so that would be 3^1 = 3
and 7(1) + 6 = 13
13 > 3 so it can't be 1

you can keep on trying it for the rest of the options

Answer 39

i'll not tell u if thats correct or not

Answer 40

it is :)

Answer 41

good for you :)

Answer 42

can you help with more?

Answer 43

ask it as a new question post ^_^

Answer 44

ok

Answer 45

(: