Please help me? ΔXYZ is translated 4 units up and 3 units left to yield ΔX′Y′Z′. What is the distance between any two corresponding points on ΔXYZ and ΔX′Y′Z′ ?
? ΔXYZ is translated 4 units up and 3 units left to yield ΔX′Y′Z′. What is the distance between any two corresponding points on ΔXYZ and ΔX′Y′Z′ ? 25 units 7 units 5 units 7√ units
Every point went up 4 units and left 3 units, right?
|dw:1447781511032:dw|
yes thats right @mathstudent55
Look at the figure above. Point X on the triangle moved up 4 and left 3. That formed a right triangle with legs 4 and 3. The distance point X moved to point X', d, is the hypotenuse of the right triangle. Do you know the Pythagoras Theorem?
\(a^2 + b^2 = c^2\) |dw:1447781676710:dw|
im not very good at math xD @mathstudent55
The Pythagoras Theorem is the formula above. In our triangle, a = 4, b = 3, and we need c. |dw:1447781756284:dw|
\(3^2 + 4^2 = d^2\) What is 3^2 ? What is 4^2 ?
9 & 16 right ? @mathstudent55
wait , i think i found the answer .... is it 5 ? @mathstudent55
Correct. 9 and 16. Now you add 9 and 16: \(25 = d^2\) That means d = 5 You are correct.
thank you so much !! @mathstudent55
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