Question

Given the position function, s of t equals t cubed divided by 3 minus 12 times t squared divided by 2 plus 36 times t, between t = 0 and t = 15, where s is given in feet and t is measured in seconds, find the interval in seconds where the particle is moving to the right.

Answer 1

\[s(t)= \frac{ t^3 }{ 3 }-\frac{ 12t^2 }{ 2 }+36t\]

Answer 2

a.0<t<6
b.5<t<15
c.t>15
d. The particle always moves to the right

Answer 3

@mathstudent55 @Mehek14

Answer 4

@Maharot