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In how many ways could you choose two different letters from the letters C, O, U, N, T? A. 60 ways B. 20 ways C. 120 ways D. 10 ways
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Does order matter?
I'm guessing it doesn't so you can use 5C2
So what this really means is \[\frac{ 5! }{ 2!(5-2)! }\]
total number of ways u can choose the 1st letter=5 no 1 letter got reduced we are left with 4 letters so total number of ways to chose the second letter=4 now look at this example-|dw:1447850791641:dw| so like this total ways=5 x 4=20
wait no
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Oh guess I was wrong :c
no wait
it depends does the sequence count? like do we consider CO and OC as diff?
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