where is the curve x^(2)y - xy - x^(2) +10x - 12y -21 = 0 symmetric?

Question

where is the curve x^(2)y - xy - x^(2)  +10x - 12y -21 = 0 symmetric?

amistre64 · Answer

what conic section is it?

amistre64 · Answer

hmm, thought it was a conic at first glance

1018 · Answer

i'm sorry im not really sure, the question is just that one.

1018 · Answer

i already forgot this one, sorry

amistre64 · Answer

it is a question from your course right?  if so then you must have material that tells you how to approach it

amistre64 · Answer

if it posted correctly, then the graph from the wolf doesnt show it as a conic

the x^2y throws it off

amistre64 · Answer

Ax^2 + By^2 +Cx + Dy+ Exy +F = 0  i believe is the form of a rotated conic

amistre64 · Answer

highest degree in this questions is 3

1018 · Answer

there are actually choices. it's x axis, y axis, origin and none

kainui · Answer

Did you just change the question?

amistre64 · Answer

ahh, then symmetry test is it

1018 · Answer

i apologize but my memory of this math is little. haha that's why im reviewing lol

1018 · Answer

no those are just the choices for the same quesiton

amistre64 · Answer

how do we test those choices?

astrophysics · Answer

Oh yay I was right, I thought I read the question wrong lol, so symmetry test does work?

amistre64 · Answer

if symmetric about the y axis: then f(-x) = f(x)

if symmetric about the x axis: then f(-x) = -f(x)

if niether, then none

amistre64 · Answer

i was thinking an axis of symmetry question meself :)

1018 · Answer

so can you teach me what to do? haha