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Mathematics 16 Online
OpenStudy (anonymous):

Find the length of segment VS. 100 cm 85 cm 150 cm 125 cm

OpenStudy (anonymous):

OpenStudy (superdavesuper):

note line UR bisects VT n SQ and it is // to VS n TQ, its length is the average of VS n TQ so UR = (VS + TQ)/2

Directrix (directrix):

Continuing, 75 = (1/2) * ( 50 + x ) where x = VS Multiply both sides by 2 and solve for x @R5lover1997

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