Which ordered pair is the solution to the system of equations?
x+y=4
x-y=-6
A.
(2, 2)
B.
(1, −7)
C.
(−1, 5)
D.
(−2, 4)
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OpenStudy (anonymous):
C
OpenStudy (anonymous):
@karolynxx @hhmorris98
OpenStudy (anonymous):
@vocaloid @Tom_Boy_Rebel
OpenStudy (anonymous):
both of those people are offline XD
OpenStudy (anonymous):
Poop
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OpenStudy (anonymous):
@MissNoName
OpenStudy (anonymous):
...what do I do?! I am starting to panic...I really need help to pass this
OpenStudy (anonymous):
Try C IDK!!?!
OpenStudy (anonymous):
:( you sure its c?
OpenStudy (anonymous):
Trust me try c
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OpenStudy (anonymous):
@kai47 are you going to help me?
lol I just got that tinge of hope XD
OpenStudy (anonymous):
ok...I put c
OpenStudy (anonymous):
-1+5=4
-1-5=-6
OpenStudy (anonymous):
do have another question now
OpenStudy (anonymous):
Oh!
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OpenStudy (anonymous):
yes
OpenStudy (anonymous):
man im too late
OpenStudy (anonymous):
I still have more
OpenStudy (anonymous):
XD
OpenStudy (anonymous):
Next
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OpenStudy (anonymous):
oh i can help
OpenStudy (anonymous):
YAY!
OpenStudy (anonymous):
Which ordered pair is the solution to the system of equations?
2x-y=-5
x+3y=22
A.
(1, 7)
B.
(4, 9)
C.
(7, 19)
D.
(8, 21)
OpenStudy (anonymous):
A
OpenStudy (anonymous):
A
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OpenStudy (anonymous):
ok, next one?
OpenStudy (anonymous):
yes next one
OpenStudy (anonymous):
k, just a sec
OpenStudy (anonymous):
Which ordered pair is the solution to the system of equations?
x+3y=12
-4x+3y=-3
A.
(0, 4)
B.
(6, 2)
C.
(3, 3)
D.
(0, −1)
OpenStudy (anonymous):
...any ideas...XD
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OpenStudy (anonymous):
Ooh i know
OpenStudy (anonymous):
yes..
OpenStudy (anonymous):
yes what...XD
OpenStudy (anonymous):
C
OpenStudy (anonymous):
just a sec im doing the equation
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OpenStudy (anonymous):
ok
OpenStudy (anonymous):
I think its C
OpenStudy (anonymous):
I agree C
OpenStudy (anonymous):
c looks right
OpenStudy (anonymous):
O_O the day has come...where everyone agrees on the same answer...
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OpenStudy (anonymous):
XD next question?
I have two more
OpenStudy (anonymous):
haha
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
You can just find where they intersect on a graphing calculator.
OpenStudy (anonymous):
Tickets to the museum cost $18 for adults and $12 for children. A group of 20 people went to the museum, and the tickets cost $324. The system of equations models this situation, where x is the number of adults and y is the number of children.
How many adults and how many children were in the group?
x+y=20
18x+12y=324
A.
8 adults and 12 children
B.
10 adults and 10 children
C.
12 adults and 8 children
D.
14 adults and 6 children
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OpenStudy (anonymous):
i once saw a question where 4 people demanded it was an answer, one thought it was C, another thoguht D, one thought A, and one thought B, it was chaos
OpenStudy (anonymous):
O_O complete chaos...
OpenStudy (anonymous):
ickets to the museum cost $18 for adults and $12 for children. A group of 20 people went to the museum, and the tickets cost $324. The system of equations models this situation, where x is the number of adults and y is the number of children.
How many adults and how many children were in the group?
x+y=20
18x+12y=324
A.
8 adults and 12 children
B.
10 adults and 10 children
C.
12 adults and 8 children
D.
14 adults and 6 children
OpenStudy (anonymous):
there...I re-posted it better XD
OpenStudy (anonymous):
Hmm, i think D
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OpenStudy (anonymous):
Hold up let me think
OpenStudy (anonymous):
Yeah most likely D
OpenStudy (anonymous):
Possibly D
OpenStudy (anonymous):
D
OpenStudy (anonymous):
k...I went with d
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OpenStudy (anonymous):
last one!
OpenStudy (anonymous):
Okay, lets see!
OpenStudy (anonymous):
A container holds a combination of dimes and nickels. There are 200 coins in all, and their total value is $16.30. The system of equations models this situation, where x is the number of dimes and y is the number of nickels.
x+y=200
0.1x+0.05y=16.3
How many dimes and nickels are in the container?
A.
126 dimes and 74 nickels
B.
132 dimes and 68 nickels
C.
84 dimes and 116 nickels
D.
112 dimes and 88 nickels
OpenStudy (anonymous):
@vzfreakz
OpenStudy (anonymous):
okay, gimme a sec
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OpenStudy (anonymous):
ok :D
OpenStudy (anonymous):
@Vocaloid
OpenStudy (anonymous):
A
OpenStudy (anonymous):
A?
anyone else agree or disagree
OpenStudy (anonymous):
Hmm, its definitly A
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OpenStudy (anonymous):
Oh!, lele yeah, its A
OpenStudy (anonymous):
Yea A
OpenStudy (anonymous):
want to know what I got...?
OpenStudy (anonymous):
ya
OpenStudy (anonymous):
yeah!
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OpenStudy (anonymous):
oh ya, someone give kai a medal too XD
OpenStudy (anonymous):
YEA!!
OpenStudy (anonymous):
oh nvm XD
OpenStudy (anonymous):
ok...I got a...
OpenStudy (anonymous):
What'd you get?
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OpenStudy (anonymous):
O_O omg...a 100%
OpenStudy (anonymous):
yay!
OpenStudy (anonymous):
100%?
OpenStudy (anonymous):
CONGRATS
OpenStudy (anonymous):
everyone...celebrate! XD
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OpenStudy (anonymous):
100%!!! YES! OMG! YES!
OpenStudy (anonymous):
YAY!
OpenStudy (anonymous):
CONGRATS YOU PASSED!!
OpenStudy (anonymous):
:D I fanned all of you XD man...you guys rock XD
OpenStudy (anonymous):
Have a nice day 😊😄
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OpenStudy (anonymous):
you guys too XD
OpenStudy (anonymous):
why are you guys still viewing this? XD you can fly away free now! XD