Question

Please check my work on conjugate diameter

Answer 1

the question says Draw the Hyperbola 16x^2-9y^2=144, the chord made by the line x=y+10, and the diameter which bisects this chord. Find the equation of the Diameter

Answer 2

i got \[y=\frac{ 16 }{ 9 }x\]for the equation of the diameter
and this is the sketch/graph that i got but i need some1 to double check it for me https://www.desmos.com/calculator/6beozmmo0d

Answer 3

ok so x=y+10 would have a slope of 1
so m=1

and i used \[y=\frac{ b^2 }{ a^2m }x\]where a^2=9 and b^2=16 and m=1

Answer 4

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