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How would I get this?? Use the rules of logarithms to condense each of the following q: log5 (a+2) +log5 (a-2) my guess: log5 .... something
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logm+log n = log mn
can u do using above law
log5 (2a-2a)???
no
I don't get how to put (a+2) & (a-2) together... :(
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log (a+2)(a-2) i am not typing base
oh its just like that?
= log (a^2-b^2)
ohhh then it would be log5 (a^2-b^2) ??
is it clear
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yes
I totally get it now :) Thanks
welcome
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