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Mathematics 12 Online
OpenStudy (anonymous):

12n^3+4n^2+3n+1

OpenStudy (anonymous):

What is the question?

OpenStudy (anonymous):

factor by grouping

OpenStudy (pawanyadav):

4n^2(3n+1)+1(3n+1) (4n^2+1)(3n+1)

OpenStudy (anonymous):

(4n^2 + 1) • (3n + 1)

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