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Given the equation of the parabola (P)\(x=ay^2+by+c\) and the exterior point \(A(x_a,y_a)\), prove that the tangents to the parabola drawn from the given point A have the equation: \[(y-y_a)=(\frac{ b+2ay_a \pm \sqrt{a(ay_a^2+by_a+c-x_a)} }{ b^2-4ac+4ax_a } )(x-x_a)\]
O my gosh...that looks REALLY confusing!
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