Question

Simplify 8 over the quantity of 2 plus 2i.

−2 + 2i
−2 − i
−2 + i
2 − 2i

Answer 1

so is this to do with complex numbers... i^2 = -1?

Answer 2

if the problem is

\[\frac{8}{2 + 2i}\]

you can multiply by the conjugate pair so it becomes

\[\frac{8}{2 + 2i} \times \frac{2 -2i}{2 - 2i}\]

you should notice this is the difference of 2 squares in the denominator, so will rationalize the denominator

hope it helps

Answer 3

2-2i that is your answer