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Find the vertex, focus, directrix, and focal width of the parabola. x = 3y2
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the general form of this type of parabola is y^2 = 4ax where the focus is at (a,0) and the directrix is x = -a
your equation can be written as y^2 = (1/3)x
so comparing this with the general for we have 4a = 1/3 do you understand this?
no ;(
what we are doing is comparing the 2 equations |dw:1448200620113:dw|
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