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Mathematics 18 Online
OpenStudy (readergirl12):

Will medal and fan..The equation is below..

OpenStudy (readergirl12):

\[7x-2[3x(x-y)+6x]\] A.\[11x-6y\] B. \[-11x+6y\] C.\[7x+6y\] D.\[-6x^2-5x+6xy\]

OpenStudy (readergirl12):

Halp -.-

jimthompson5910 (jim_thompson5910):

This is not an equation since there are no equal signs. Anyways, your first step is to distribute what is 3x(x-y) equal to when you distribute?

OpenStudy (readergirl12):

I don't know what you mean.. ;-;

OpenStudy (mathmale):

It's important that you include the instructions when you post a problem. What are you supposed to do in this problem?

jimthompson5910 (jim_thompson5910):

have you seen the distribution property before? something like 2*(x+3y) = 2*x + 2*3y = 2x + 6y

OpenStudy (readergirl12):

@mathmale I don't know.. This is how it came.. An yes I've seen that.. Is it 3x^2 -3xy?..v-v

jimthompson5910 (jim_thompson5910):

`3x(x-y) ` will turn into `3x^2-3xy`, yes correct

jimthompson5910 (jim_thompson5910):

So `7x - 2[3x(x-y)+6x]` turns into `7x - 2[3x^2-3xy+6x]`

jimthompson5910 (jim_thompson5910):

now we must distribute the -2 through to each term inside the square brackets what is ` - 2[3x^2-3xy+6x]` equal to?

OpenStudy (readergirl12):

-6x(2+x-y)?

jimthompson5910 (jim_thompson5910):

-2 times 3x^2 = _____ (fill in the blank)

OpenStudy (mathmale):

I'd suggest you be really clear what you're looking for, what you're trying to do, what the question asks. Seeing that there is no = sign in the given expression, I'd venture that the instructions say, "Simplify by combining like terms."

OpenStudy (readergirl12):

\[-6x^2\] @jim_thompson5910 ?

OpenStudy (mathmale):

Expand, and then combine like terms to simplify the following: 7x-2[3x(x-y)+6x]

jimthompson5910 (jim_thompson5910):

yes @readergirl12

jimthompson5910 (jim_thompson5910):

-2 times -3xy = _____ (fill in the blank)

OpenStudy (readergirl12):

6xy

jimthompson5910 (jim_thompson5910):

yes

jimthompson5910 (jim_thompson5910):

-2 times 6x = _______

OpenStudy (readergirl12):

-12x

jimthompson5910 (jim_thompson5910):

So `-2[3x^2-3xy+6x]` turns into `-6x^2+6xy-12x`

jimthompson5910 (jim_thompson5910):

which means `7x - 2[3x^2-3xy+6x]` turns into `7x - 6x^2+6xy-12x`

jimthompson5910 (jim_thompson5910):

now combine like terms in `7x - 6x^2+6xy-12x`

OpenStudy (readergirl12):

How is that done?

jimthompson5910 (jim_thompson5910):

hopefully you see that 7x and -12x are the only pair of like terms?

OpenStudy (readergirl12):

Yep.

jimthompson5910 (jim_thompson5910):

what would they combine to?

OpenStudy (readergirl12):

\[x^7 -12x ?\]

jimthompson5910 (jim_thompson5910):

idk where you're getting x^7 but I agree with the fact that 7x-12x = -5x

jimthompson5910 (jim_thompson5910):

There are no other like terms to combine. So we're done with the problem `7x - 6x^2+6xy-12x` becomes `-6x^2-5x+6xy` In the end, `7x - 2[3x(x-y)+6x]` is equivalent to `-6x^2-5x+6xy`

jimthompson5910 (jim_thompson5910):

oh nvm I misread what you wrote. You should have 7x and -12x combine to -5x since 7-12 = -5

OpenStudy (readergirl12):

So.. It's 10x or no?

jimthompson5910 (jim_thompson5910):

where are you getting 10x ?

OpenStudy (readergirl12):

Ehhh.. Thought you told me to combine 7x -12x and 5x,Sorry. -.-

jimthompson5910 (jim_thompson5910):

oh I see, no once you combine 7x and -12x, those two terms go away and are replaced with -5x

OpenStudy (readergirl12):

Mkay..Anything else need to be done?

jimthompson5910 (jim_thompson5910):

nope, `-6x^2-5x+6xy` is as simplified as it gets

OpenStudy (readergirl12):

Woooow.. That took longer than I thought..Well Thank youuu Here's your cookie.. ♥♥|dw:1448235580767:dw|

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