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Prove Sec^2ΘCot^2Θ=Csc^2Θ
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\[\sin ^{2}\theta Cot ^{2}\theta = Csc ^ {2}\theta\]
is that first term sec^2 ? or sin^2 ?
I'm going to assume sec^2
Hint: \[\Large \sec^2(\theta)\cot^2(\theta)=\csc^2(\theta)\] \[\Large \frac{1}{\cos^2(\theta)}*\frac{\cos^2(\theta)}{\sin^2(\theta)}=\csc^2(\theta)\]
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