Question

(1/4)*(2^-3)*64*((3/2)^3)*(2^0) solve this step by step piles will give coins

Answer 1

use the 'order of operations' rule

sometimes called PEMDAS

P stands for parentheses (or brackets)

so FIRST work out the individual values inside the brackets:

2^-3
(3/2)^3
2^0

write those values here...

Answer 2

i got it i made a small mistake
:P