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Solve. 8x + 4 ≤ –20 A. x ≥ –2 B. x ≤ –3 C. x ≤ –2 D. x ≥ –3
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@Brooklyn_Boiii
\[\huge~\rm~8x + 4 -4≤ –20-4\] subtract 4 from both sides what are you left with?
0 and 16 I think
good so we have \[\huge~\rm~8x≤–16\] divide both sides by 8
\[\huge~\rm~ 8x/8≤–16/8\]
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1 and 2
good so \[\huge~\rm~ x≤-2\]
thanks
np
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