Question

If a net horizontal force of 130 N is applied to a person with mass 60.0 kg who is resting on the edge of a swimming pool, what horizontal acceleration is produced?

Answer 1

Newton's Second law

\(\rm {F_{net}=m_T \cdot~a}\)

a : acceleration
F : Net force applied
m : total mass


so here you can find acceleration by :
\[\rm a=\frac{ F_{Net} }{ m_T }\]

Answer 2

that's right! @rvc