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Mathematics 21 Online
OpenStudy (anonymous):

PLZ HELP WILL MEDAL AND FAN!! For the table, determine whether the relationship is a linear function. Then represent the relationship using words, an equation, and a graph.

OpenStudy (anonymous):

OpenStudy (anonymous):

@AskMeLotss

OpenStudy (andrewherpeche):

you are so cute and i wish i could help but idk it

OpenStudy (anonymous):

ok thx for trying :)

OpenStudy (anonymous):

@Hero

OpenStudy (welshfella):

Notice that for each increase of 1 in x , y increases by 3. So y is increasing in constant steps for each increase of 1 ib x Do you think this is a linear function? If you drew a graph would it be a straight line?

OpenStudy (anonymous):

ya

OpenStudy (anonymous):

i think its a linear functon

OpenStudy (welshfella):

you are right one more thing y has a starting value of 5 when x = 0 also the slope of the line will be 3 because y is increasing in steps of 3

OpenStudy (welshfella):

straight lines have a standard equation y = mx + b where m = slope and b is the value of y when x = 0 so what do you think the equation be?

OpenStudy (anonymous):

but 0+3 doesn't = 5 ??????

OpenStudy (welshfella):

m = 3 and b = 5 right?

OpenStudy (anonymous):

i guess

OpenStudy (welshfella):

so plug those values into the standard form

OpenStudy (anonymous):

ok

OpenStudy (welshfella):

y = 3x + what?

OpenStudy (anonymous):

5?

OpenStudy (welshfella):

yes y = 3x + 5 is the required equation now you see why y = 5 when x = 0 plug in x = 0:- y = 3(0) + 5 y = 0 + 5 y = 5

OpenStudy (anonymous):

ohhh okay now i get it

OpenStudy (welshfella):

if you draw the graph it will look something like |dw:1448294279926:dw|

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