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Algebra 11 Online
OpenStudy (anonymous):

solve the equation below by completing the square and then solving for x. x^2+12x=0 A. (x+3/2)^2=9/2 B. (x+3)^2=9 (x+6)^2=36 (x+12)^2=144

OpenStudy (anonymous):

your answer is d

OpenStudy (anonymous):

How would i work it out?

OpenStudy (campbell_st):

if you have \[x^2 + bx + ? \] to complete the square you need to add \[(\frac{b}{2})^2\] to both sides of the equation... you have a b value of 12 halve it... then square it

OpenStudy (campbell_st):

and the answer isn't D

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