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http://s29.postimg.org/3v0o0dk7r/image.jpg How to do c)? I try to do, but i dont get the right answer. I dont know where to put that minus o.o the answer is 2 2/3 (8/3)
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Try to separate it like this: \[x ^{a-b}=\frac{ x ^{a} }{ xb }\]
But i dont understand how.. Sorry im new at log and stuff like that>.<
Also don't forget that: \[-\log _{a}(x) =\log _{a}(x ^{-1})\] and \[a ^{\log _{a}(x)}=x\]
Can you show me how far you got ?
@Cherryboa
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When i try to do i get 1/3 not 8/3 .-.
Yay i did it ^^
http://s2.postimg.org/nay8sahp5/image.jpg <-- i did like that, so thanks for your help, bcuz i didnt know about first rule u showed me
No probs =)
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