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MEDAL!!! Find the minimum or maximum value of the parabola for the following equation: f(x) = 2(x- 3)^2 + 4
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Would the minimum value be (3,4) or simply 4?
y = (x - h)^2 + k vertex is (h,k)
It would be (3,4). :)
Thank you!
Anytime! :D
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