Question

find x intercept of a parabola when vertex is (1,1) and y-intercept is (0,-3)

Answer 1

ans: x -intercepts at 1/2 and 3/2

Answer 2

Oh it says y oh ok

Answer 3

HI!!

Answer 4

first we can find the equation for the parabola then we can set it equal to zero and solve

Answer 5

in vertex from is looks like \[y=a(x-1)^2+1\] and we need \(a\)

Answer 6

if \(x=0\) you are told that \(y=-3\) then we get \[-3=a(0-1)^2+1\]or \[-3=a+1\] making \[a=-4\]

Answer 7

set \[-4(x-1)^2+1=0\] and solve for \(x\)