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What is the solution to the system of equations represented by the two equations? y= 3/2x y= -1/2x+4
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y= 3/2x <----Equation 1 y= -1/2x+4 <----Equation 2 We know the value of y already its given so take equation 1 and plug it into equation 2 \[\huge~\rm~3/2x=-1/2x+4 \] solve for x
so it would be (3,2)
i think it might be (2, 3) instead @rockycatsrule
ok thx
because when i solved for x it came out as 2
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