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Algebra 11 Online
OpenStudy (anonymous):

solve equation if necessary round to the nearest tenth. x^2=256...there is multiple choice if u would like them

OpenStudy (freckles):

try taking square root of both sides... there will be two solutions

OpenStudy (anonymous):

16?

OpenStudy (freckles):

that is one solution

OpenStudy (freckles):

16*16 is 256 what other number times itself is 256

OpenStudy (anonymous):

and -16 im assuming

OpenStudy (freckles):

yes 16*16=256 and -16*-16=256 so both 16 and -16 are solutions to x^2=256

OpenStudy (freckles):

And we say the solutions are x=16 or x=-16 or you can write in set notation \[x \in \{-16,16\}\]

OpenStudy (anonymous):

thankyou!1

OpenStudy (freckles):

np

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