Question

help

Answer 1

easy:
\[\frac{ n^2+n-6 }{ 3n^2-8n+4 }=\frac{ (n-2)*(n+3) }{ (3n-2)*(n-2) }=\frac{ \cancel {(n-2)}*(n+3) }{ (3n-2)* \cancel {(n-2)} }\]

Answer 2

you need to factor both equations and then simplify

Answer 3

so it A correct

Answer 4

yeah

Answer 5

thanks