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Mathematics 7 Online
OpenStudy (anonymous):

can someone help me ??

rebeccaxhawaii (rebeccaxhawaii):

question

OpenStudy (anonymous):

2(3p-11)- ≥16

OpenStudy (anonymous):

*2(3p-11) ≥-16

pooja195 (pooja195):

Start by distributing the 2 to the rest of the equation |dw:1448480455655:dw|

pooja195 (pooja195):

2 x 3 =?

OpenStudy (anonymous):

6

pooja195 (pooja195):

Good so 6p 2 x -11=?

OpenStudy (anonymous):

-22?

pooja195 (pooja195):

good now we have \[\huge~\rm~\bf6p-22 ≥16\] Next step is to add 22 to both sides because we are isolating x \[\huge~\rm~\bf6p-22 +22≥16+22=?\]

OpenStudy (anonymous):

6p ≥38

pooja195 (pooja195):

Wait you changed it

pooja195 (pooja195):

good now we have \[\huge~\rm~\bf6p-22 ≥-16\] Next step is to add 22 to both sides because we are isolating x \[\huge~\rm~\bf6p-22 +22≥-16+22=?\]

OpenStudy (anonymous):

oh jk

pooja195 (pooja195):

lol sorry

OpenStudy (anonymous):

6p≥6

pooja195 (pooja195):

Good now divide both sides by 6 \[\huge~\rm~6p/6≥6 /6\]

pooja195 (pooja195):

What are you left with? :)

OpenStudy (anonymous):

p ≥1

OpenStudy (anonymous):

thank you!!

pooja195 (pooja195):

No problem =)

OpenStudy (anonymous):

hi

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