Question

Need help with logarithms please...
http://imgur.com/mJQ6yhF
I sorta kinda get them..

Answer 1

first i'd do ...
\[\log_{4}16a+\log_{4}\sqrt{b} -\log_{4}c ^{3} -\log_{4}d ^{3} \]

Right?

Answer 2

Right and log16a=2+loga

Answer 3

oh tru that. so basically.... let me write this out..

Answer 4

we'll ignore base 4 for now.
2+loga+logb^1/2-logc^3-logd^3

then that'd equal this right?
2+logA+1/2logb-3logc-3logd?

Answer 5

Yes if it is d^3 in question

Answer 6

woops, got ahead of myself lol.
So first i take out ^3 on D.
But would that be my final answer?
2+loga+1/2logb-3logc-logd?

Answer 7

Yed

Answer 8

Thank you very much :),
would you mind helping me on one more logarithm problem if i repoen another thread?

Answer 9

Yes I'm there for another

Answer 10

Cool i'll @ u :)