Ask your own question, for FREE!
Mathematics 8 Online
OpenStudy (yoloshroom):

Need help with logarithms please... http://imgur.com/mJQ6yhF I sorta kinda get them..

OpenStudy (yoloshroom):

first i'd do ... \[\log_{4}16a+\log_{4}\sqrt{b} -\log_{4}c ^{3} -\log_{4}d ^{3} \] Right?

OpenStudy (pawanyadav):

Right and log16a=2+loga

OpenStudy (yoloshroom):

oh tru that. so basically.... let me write this out..

OpenStudy (yoloshroom):

we'll ignore base 4 for now. 2+loga+logb^1/2-logc^3-logd^3 then that'd equal this right? 2+logA+1/2logb-3logc-3logd?

OpenStudy (pawanyadav):

Yes if it is d^3 in question

OpenStudy (yoloshroom):

woops, got ahead of myself lol. So first i take out ^3 on D. But would that be my final answer? 2+loga+1/2logb-3logc-logd?

OpenStudy (pawanyadav):

Yed

OpenStudy (yoloshroom):

Thank you very much :), would you mind helping me on one more logarithm problem if i repoen another thread?

OpenStudy (pawanyadav):

Yes I'm there for another

OpenStudy (yoloshroom):

Cool i'll @ u :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
Arriyanalol: i need help
10 hours ago 7 Replies 1 Medal
Arriyanalol: CONGRATS to me
13 hours ago 8 Replies 2 Medals
Legomaster346: What colleges are good that are near Arab Alabama?
1 week ago 5 Replies 0 Medals
Arriyanalol: i need help
1 week ago 6 Replies 2 Medals
Arizona: does anyone know the percentage rate of 30,000 and 40,000
1 week ago 0 Replies 0 Medals
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!