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Need help with logarithms please... http://imgur.com/mJQ6yhF I sorta kinda get them..
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first i'd do ... \[\log_{4}16a+\log_{4}\sqrt{b} -\log_{4}c ^{3} -\log_{4}d ^{3} \] Right?
Right and log16a=2+loga
oh tru that. so basically.... let me write this out..
we'll ignore base 4 for now. 2+loga+logb^1/2-logc^3-logd^3 then that'd equal this right? 2+logA+1/2logb-3logc-3logd?
Yes if it is d^3 in question
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woops, got ahead of myself lol. So first i take out ^3 on D. But would that be my final answer? 2+loga+1/2logb-3logc-logd?
Yed
Thank you very much :), would you mind helping me on one more logarithm problem if i repoen another thread?
Yes I'm there for another
Cool i'll @ u :)
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