Question

Another BOOLEAN REDUCTION:

Hello again, got another boolean reduction this one should be much simpler

Answer 1

Tell me if I'm right or wrong

I have:

~B~D(~A~C + AC) + BD(~A~C + AC) = ~B~D + BD

Answer 2

one more step

Answer 3

Well we can change it to NOTXOR

Is that what you mean?

Answer 4

You have used this identity to simplify so far
~X~Y + XY = 1
Use it one more time.

Answer 5

You're right not sure why I didn't see that then, Thank you!